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EXAMPLE 46. Solar physicist Balfour Stewart identified Four Short Term Sunspot Cycles. (A). The Sun’s rotation period = 24.66225 Earth days. The Four Short Term Sunspot Cycles are:- (B). 24.011 Earth days. (C). 32.955 Earth days. (D). 26.871 Earth days. (E). 24.142 Earth days. This image depicts the ANGLES rotated by Jupiter (The LARGEST Planet in The Solar System) during TWICE each of the above time periods.
Once again, we see (glaringly, blindingly obvious!) “OCTANT HUGGING”. Once again Newtonian Physics is absolutely impotent as far as providing an explanation.
DEMONSTRATION:-
Jupiter’s rotation period = 0.41353831 Earth days.
(A). 2 x 24.66225 = 49.3245 Earth days.
During 49.3245 Earth days, Jupiter rotates
(49.3245 ÷ 0.41353831 = 119.2743 rotations.
0.2743 x 360 = 98.8 degrees.
That is 119 complete rotations + 98.8 degrees.
(B). 2 x 24.011 = 48.022 Earth days.
During 48.022 Earth days, Jupiter rotates
(48.022 ÷ 0.41353831 = 116.1247 rotations.
0.1247 x 360 = 44.9 degrees.
That is 116 complete rotations + 44.9 degrees.
(C). 2 x 32.955 = 65.91 Earth days.
During 65.91 Earth days, Jupiter rotates
(65.91 ÷ 0.41353831 = 159.3806 rotations.
0.3806 x 360 = 137.0 degrees.
That is 159 complete rotations + 137.0 degrees.
(D). This period “fails” The Octants Rule, and is therefore excluded from the image.
(E). 2 x 24.142 = 48.284 Earth days.
During 48.284 Earth days, Jupiter rotates
(48.284 ÷ 0.41353831 = 116.7582 rotations.
0.7582 x 360 = 272.96 degrees.
That is 116 complete rotations + 272.96 degrees.
To verify the time periods in this example, click on the following links:-
For The Sun’s rotation period
www.solarsystemtimeperiods.com/planet-orbital
For Jupiter’s rotation period
www.solarsystemtimeperiods.com/jup-rot
For The Sunspot periods
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